teja

• May 24th, 2012

 

We use 30% mortar in brick work, so 1 cum of brickwork has 0.3 cum of mortar.quantity for 1:6 mortar mix
cement quantity= 1/(1+6)*0.3
and sand= 6/(1+6)*0.3

Ashish thakur

• Oct 17th, 2012

 

sum 1+6=7
total dry mortar required for 1 cu m brick masonry=.30 cu m

cement=(1*.30)/7=.04

SACHIN

• Oct 3rd, 2013

 

dry Volume - 30%, so Total Qty is 1.3 m3,
Cement = (1x1.3)/ (1+6) = .1857 m3
Cement 1 Bag = 0.0347 m3
So, Cement = 0.1857/0.347 = 5.35 Bags.

vijay

• Oct 18th, 2013

 

1cum B.W requried-500 nos
b.w in C.M1;6 requried-0.25cum
cement-1440/6=240Kg
240*.25=60=1.2bags

galaydh

• Oct 23rd, 2013

 

1*3.1/7=0.44CUBIC
1CEMENT=O.O35 CUMIC
SO 0.44/0.035=12.7 CEMENT

B.Mohamed Mansoor

• Nov 3rd, 2013

 

Ratio 1:6
Let 1:6 so we take 1+6=7
1 time of cement so 1/7=0.142
if plastering mean=1.52
so 0.142*1.52=0.21
density of sand 1440
so 0.21*1440=1.45 Bag/cum
and 72.5 kg/cum


as per is 456

B.Mohamed mansoor

• Nov 6th, 2013

 

Ratio 1:6
Let 1:6 so we take 1+6=7
1 time of cement so 1/7=0.142
if plastering mean=1.52
so 0.142*1.52=0.21
density of sand 1440
so 0.21*1440=309.6 kg
and 6.192 bag..

Md. Nesar Uddin

 Profile Answers by Md. Nesar Uddin 

• Jan 12th, 2014

 

We know, for 1 cum brickwork done to need 35% dry cement mortar.
So, Cement Mortar for 1 cum=1 ×0.35=0.35 cum
Given, Ratio is 1:6 = 1+6 = 7
1. Cement= (0.35×1)/7=0.05 cum.
2. Sand= (0.35×6)/7=0.3 cum

Md. Nesar Uddin, PowerPac, Bangladesh.

• Jan 12th, 2014

 

We know, for 1 cum brickwork done to need 35% dry cement mortar.
So, Cement Mortar for 1 cum=1 ×0.35=0.35 cum
Given, Ratio is 1:6 = 1+6 = 7
1. Cement= (0.35×1)/7=0.05 cum.
2. Sand= (0.35×6)/7=0.3 cum